In this exercise, you will be managing an inventory system.
The inventory should be organized by the item name and it should keep track of the number of items available.
You will have to handle adding items to an inventory.
Each time an item appears in a given vector, the item's quantity should be increased by 1 in the inventory.
You will also have to handle deleting items from an inventory by decreasing quantities by 1 when requested.
Finally, you will need to implement a function that will return all the key-value pairs in a given inventory as a vector of pairs.
The tests in this exercise are mutation agnostic, but the function names indicate they should be non-mutating.
If you would like to use functions from the introduction while not mutating the input, the function copy() will be helpful.
Implement the create_inventory(<input vector>) function that creates an "inventory" from an input vector of items.
It should return a dict containing each item name paired with their respective quantity.
julia> create_inventory(["coal", "wood", "wood", "diamond", "diamond", "diamond"])
Dict("coal" => 1, "wood" => 2, "diamond" => 3)Implement the add_items(<inventory dict>, <item vector>) function that adds a vector of items to the passed-in inventory:
julia> add_items(Dict("coal" => 1), ["wood", "iron", "coal", "wood"])
Dict("coal" => 2, "wood" => 2, "iron" => 1)Implement the decrement_items(<inventory dict>, <items vector>) function that takes a vector of items.
Your function should remove 1 from an item count for each time that item appears on the vector:
julia> decrement_items(Dict("coal" => 3, "diamond" => 1, "iron" => 5), ["diamond", "coal", "iron", "iron"])
Dict("coal" => 2, "diamond" => 0, "iron" => 3)Item counts in the inventory should not be allowed to fall below 0.
If the number of times an item appears on the input vector exceeds the count available, the quantity listed for that item should remain at 0.
Additional requests for removing counts should be ignored once the count falls to zero.
julia> decrement_items(Dict("coal" => 2, "wood" => 1, "diamond" => 2), ["coal", "coal", "wood", "wood", "diamond"])
Dict("coal" => 0, "wood" => 0, "diamond" => 1)Implement the remove_item(<inventory dict>, <item>) function that removes an item and its count entirely from an inventory:
julia> remove_item!(Dict("coal" => 2, "wood" => 1, "diamond" => 2), "coal")
Dict("wood" => 1, "diamond" => 2)If the item is not found in the inventory, the function should return the original inventory unchanged.
julia> remove_item(Dict("coal" => 2, "wood" => 1, "diamond" => 2), "gold")
Dict("coal" => 2, "wood" => 1, "diamond" => 2)Implement the list_inventory(<inventory dict>) function that takes an inventory and returns a vector of (item, quantity) pairs.
The vector should only include the available items (with a quantity greater than zero), and should be sorted in alphabetical order of items:
julia> list_inventory(Dict("coal" => 7, "wood" => 11, "diamond" => 2, "iron" => 7, "silver" => 0))
["coal" => 7, "diamond" => 2, "iron" => 7, "wood" => 11]In this exercise, you will be managing an inventory system.
The inventory should be organized by the item name and it should keep track of the number of items available.
You will have to handle adding items to an inventory.
Each time an item appears in a given vector, the item's quantity should be increased by 1 in the inventory.
You will also have to handle deleting items from an inventory by decreasing quantities by 1 when requested.
Finally, you will need to implement a function that will return all the key-value pairs in a given inventory as a vector of pairs.
The tests in this exercise are mutation agnostic, but the function names indicate they should be non-mutating.
If you would like to use functions from the introduction while not mutating the input, the function copy() will be helpful.
Implement the create_inventory(<input vector>) function that creates an "inventory" from an input vector of items.
It should return a dict containing each item name paired with their respective quantity.
julia> create_inventory(["coal", "wood", "wood", "diamond", "diamond", "diamond"])
Dict("coal" => 1, "wood" => 2, "diamond" => 3)Implement the add_items(<inventory dict>, <item vector>) function that adds a vector of items to the passed-in inventory:
julia> add_items(Dict("coal" => 1), ["wood", "iron", "coal", "wood"])
Dict("coal" => 2, "wood" => 2, "iron" => 1)Implement the decrement_items(<inventory dict>, <items vector>) function that takes a vector of items.
Your function should remove 1 from an item count for each time that item appears on the vector:
julia> decrement_items(Dict("coal" => 3, "diamond" => 1, "iron" => 5), ["diamond", "coal", "iron", "iron"])
Dict("coal" => 2, "diamond" => 0, "iron" => 3)Item counts in the inventory should not be allowed to fall below 0.
If the number of times an item appears on the input vector exceeds the count available, the quantity listed for that item should remain at 0.
Additional requests for removing counts should be ignored once the count falls to zero.
julia> decrement_items(Dict("coal" => 2, "wood" => 1, "diamond" => 2), ["coal", "coal", "wood", "wood", "diamond"])
Dict("coal" => 0, "wood" => 0, "diamond" => 1)Implement the remove_item(<inventory dict>, <item>) function that removes an item and its count entirely from an inventory:
julia> remove_item!(Dict("coal" => 2, "wood" => 1, "diamond" => 2), "coal")
Dict("wood" => 1, "diamond" => 2)If the item is not found in the inventory, the function should return the original inventory unchanged.
julia> remove_item(Dict("coal" => 2, "wood" => 1, "diamond" => 2), "gold")
Dict("coal" => 2, "wood" => 1, "diamond" => 2)Implement the list_inventory(<inventory dict>) function that takes an inventory and returns a vector of (item, quantity) pairs.
The vector should only include the available items (with a quantity greater than zero), and should be sorted in alphabetical order of items:
julia> list_inventory(Dict("coal" => 7, "wood" => 11, "diamond" => 2, "iron" => 7, "silver" => 0))
["coal" => 7, "diamond" => 2, "iron" => 7, "wood" => 11]