Name Badges
10 Points
nothingness
Instructions
In this exercise you'll be writing code to print name badges for factory employees.
Employees have an ID, name, and department name.
Employee badge labels are formatted as follows: "[id] - name - DEPARTMENT".
1. Print a badge for an employee
Implement the print_name_badge function. It should take an ID, name, and a department.
It should return the badge label, with the department name in uppercase.
print_name_badge(67, "Katherine Williams", "Strategic Communication")
# => "[67] - Katherine Williams - STRATEGIC COMMUNICATION"2. Print a badge for a new employee
Due to a quirk in the computer system, new employees occasionally don't yet have an ID when they start working at the factory. As badges are required, they will receive a temporary badge without the ID prefix.
Extend the print_name_badge function. When the id is missing, it should print a badge without it.
print_name_badge(NA, "Robert Johnson", "Procurement")
# => "Robert Johnson - PROCUREMENT"3. Print a badge for the owner
Even the factory's owner has to wear a badge at all times.
However, an owner does not have a department and never will: they are above all the departments.
In this case, the label should print "OWNER" instead of the department name.
Extend the print_name_badge function. When the department is NULL, assume the badge belongs to the company owner.
print_name_badge(204, "Rachel Miller", NULL)
# => "[204] - Rachel Miller - OWNER"Note that it is possible for the owner to also be a new employee.
print_name_badge(NA, "Rachel Miller", NULL)
# => "Rachel Miller - OWNER"4. Calculate the total salary of employees with no ID
As a rough metric of how well the IDs are being issued, you want to see the combined salary of employees with no ID. A high value means lots are waiting, or the problem is affecting senior people: both are bad.
Implement the salaries_no_id function that takes a vector of IDs and a corresponding vector of salaries, and returns the sum of salaries for people with no ID yet.
Both vectors are the same length.
ids <- c(204, NA, 210, 352, NA, 263)
salaries <- c(23, 21, 47, 35, 17, 101) * 1000
salaries_no_id(ids, salaries)
# => 38,000As an untested extra learning: If there are no employees without ID, what is the "empty vector" that you are summing?
Name Badges
10 Points
nothingness
Instructions
In this exercise you'll be writing code to print name badges for factory employees.
Employees have an ID, name, and department name.
Employee badge labels are formatted as follows: "[id] - name - DEPARTMENT".
1. Print a badge for an employee
Implement the print_name_badge function. It should take an ID, name, and a department.
It should return the badge label, with the department name in uppercase.
print_name_badge(67, "Katherine Williams", "Strategic Communication")
# => "[67] - Katherine Williams - STRATEGIC COMMUNICATION"2. Print a badge for a new employee
Due to a quirk in the computer system, new employees occasionally don't yet have an ID when they start working at the factory. As badges are required, they will receive a temporary badge without the ID prefix.
Extend the print_name_badge function. When the id is missing, it should print a badge without it.
print_name_badge(NA, "Robert Johnson", "Procurement")
# => "Robert Johnson - PROCUREMENT"3. Print a badge for the owner
Even the factory's owner has to wear a badge at all times.
However, an owner does not have a department and never will: they are above all the departments.
In this case, the label should print "OWNER" instead of the department name.
Extend the print_name_badge function. When the department is NULL, assume the badge belongs to the company owner.
print_name_badge(204, "Rachel Miller", NULL)
# => "[204] - Rachel Miller - OWNER"Note that it is possible for the owner to also be a new employee.
print_name_badge(NA, "Rachel Miller", NULL)
# => "Rachel Miller - OWNER"4. Calculate the total salary of employees with no ID
As a rough metric of how well the IDs are being issued, you want to see the combined salary of employees with no ID. A high value means lots are waiting, or the problem is affecting senior people: both are bad.
Implement the salaries_no_id function that takes a vector of IDs and a corresponding vector of salaries, and returns the sum of salaries for people with no ID yet.
Both vectors are the same length.
ids <- c(204, NA, 210, 352, NA, 263)
salaries <- c(23, 21, 47, 35, 17, 101) * 1000
salaries_no_id(ids, salaries)
# => 38,000As an untested extra learning: If there are no employees without ID, what is the "empty vector" that you are summing?