172. Factorial Trailing Zeroes
Given an integer n, return the number of trailing zeroes in n!.
Note that n! = n * (n - 1) * (n - 2) * ... * 3 * 2 * 1.
Examples
Example 1
Input: n = 3
Output: 0
Explanation: 3! = 6, no trailing zero.
Example 2
Input: n = 5
Output: 1
Explanation: 5! = 120, one trailing zero.
Example 3
Input: n = 0
Output: 0
Follow Up
- Could you write a solution that works in logarithmic time complexity?