Longest Palindrome After Substring Concatenation II - Practice Coding | SlaveCode
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3504. Longest Palindrome After Substring Concatenation II
Hard
50 Points
Two Pointers
String
Dynamic Programming
You are given two strings, s and t.
You can create a new string by selecting a substring from s (possibly empty) and a substring from t (possibly empty), then concatenating them in order.
Return the length of the longest palindrome that can be formed this way.
Examples
Example 1
Input: s = "a", t = "a"
Output: 2
Explanation:
Concatenating "a" from s and "a" from t results in "aa" , which is a palindrome of length 2.
Example 2
Input: s = "abc", t = "def"
Output: 1
Explanation:
Since all characters are different, the longest palindrome is any single character, so the answer is 1.
Example 3
Input: s = "b", t = "aaaa"
Output: 4
Explanation:
Selecting " aaaa " from t is the longest palindrome, so the answer is 4.
Example 4
Input: s = "abcde", t = "ecdba"
Output: 5
Explanation:
Concatenating "abc" from s and "ba" from t results in "abcba" , which is a palindrome of length 5.
Constraints
1 <= s.length, t.length <= 1000
s and t consist of lowercase English letters.
3504. Longest Palindrome After Substring Concatenation II
Hard
50 Points
Two Pointers
String
Dynamic Programming
You are given two strings, s and t.
You can create a new string by selecting a substring from s (possibly empty) and a substring from t (possibly empty), then concatenating them in order.
Return the length of the longest palindrome that can be formed this way.
Examples
Example 1
Input: s = "a", t = "a"
Output: 2
Explanation:
Concatenating "a" from s and "a" from t results in "aa" , which is a palindrome of length 2.
Example 2
Input: s = "abc", t = "def"
Output: 1
Explanation:
Since all characters are different, the longest palindrome is any single character, so the answer is 1.
Example 3
Input: s = "b", t = "aaaa"
Output: 4
Explanation:
Selecting " aaaa " from t is the longest palindrome, so the answer is 4.
Example 4
Input: s = "abcde", t = "ecdba"
Output: 5
Explanation:
Concatenating "abc" from s and "ba" from t results in "abcba" , which is a palindrome of length 5.