Minimum Numbers of Function Calls to Make Target Array - Practice Coding | SlaveCode
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1558. Minimum Numbers of Function Calls to Make Target Array
Medium
30 Points
Array
Greedy
Bit Manipulation
You are given an integer array nums. You have an integer array arr of the same length with all values set to 0 initially. You also have the following modify function:
You want to use the modify function to convert arr to nums using the minimum number of calls.
Return the minimum number of function calls to make nums from arr.
The test cases are generated so that the answer fits in a 32-bit signed integer.
Examples
Example 1
Input: nums = [1,5]
Output: 5
Explanation: Increment by 1 (second element): [0, 0] to get [0, 1] (1 operation).
Double all the elements: [0, 1] -> [0, 2] -> [0, 4] (2 operations).
Increment by 1 (both elements) [0, 4] -> [1, 4] -> [1, 5] (2 operations).
Total of operations: 1 + 2 + 2 = 5.
Example 2
Input: nums = [2,2]
Output: 3
Explanation: Increment by 1 (both elements) [0, 0] -> [0, 1] -> [1, 1] (2 operations).
Double all the elements: [1, 1] -> [2, 2] (1 operation).
Total of operations: 2 + 1 = 3.
1558. Minimum Numbers of Function Calls to Make Target Array
Medium
30 Points
Array
Greedy
Bit Manipulation
You are given an integer array nums. You have an integer array arr of the same length with all values set to 0 initially. You also have the following modify function:
You want to use the modify function to convert arr to nums using the minimum number of calls.
Return the minimum number of function calls to make nums from arr.
The test cases are generated so that the answer fits in a 32-bit signed integer.
Examples
Example 1
Input: nums = [1,5]
Output: 5
Explanation: Increment by 1 (second element): [0, 0] to get [0, 1] (1 operation).
Double all the elements: [0, 1] -> [0, 2] -> [0, 4] (2 operations).
Increment by 1 (both elements) [0, 4] -> [1, 4] -> [1, 5] (2 operations).
Total of operations: 1 + 2 + 2 = 5.
Example 2
Input: nums = [2,2]
Output: 3
Explanation: Increment by 1 (both elements) [0, 0] -> [0, 1] -> [1, 1] (2 operations).
Double all the elements: [1, 1] -> [2, 2] (1 operation).
Total of operations: 2 + 1 = 3.